How Did the Trayvon Martin Case Turn into a Racial Issue?

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I take print-outs of the questions/answers on this forum, and read them couple times before going to bed. My secretary files them before micro-fiche'ing them for me in the morning. That data is backed up in 3 different places in the US for disaster recovery purposes. That will be the legacy that I will leave for my progeny :-)

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Is there a Stack Exchange site for shopping, e.g., men's wear?

No, and it's pretty unlikely. While there's been a few experiments, with product recommendations sites, it's not really something that fits the Q&A model very well. Website recommendations (specific as in your case or general) aren't something that's happened yet and what a "good online shop" is is kinda ultra subjective and not a great subject for a question

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Is this hypothetical system secure?

First vulnerability is around using SHA1 hashes. SHA1 hash based collisions are relatively highly probable with modern compute power. See SHA1-collisionsWhat this means is the rogue party can capture those hashes on the wire and brute force them. Even worse, if the attacker gets into your server and obtains the limited set allowed, it narrows down the problem significantly

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How do you win against the superiority of NPC Lords?

Get your party skills up (First Aid, Surgery, Wound Treatment).Get alot of cavalry and Sergeants, (Swadian Knights, Any Sergeant*)With this set up, every confrontation you have with 600 army you'll pick off 50 men after each battle and they'll let you leave, after that rest for a while and attack again. Repeat until domination.You could call it raiding them

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To find complement of an event (Conditional Probability )

Let the number of men who get their own hat be represented by the random variable $M$.Then, using $$ for 'is exactly':

$$P(M0)P(M1)P(M3)1$$$P(M2)0$ because if two men get their own hat, so does the third.The complement of $P(M0)$ is $1-P(M0)$, and$$1-P(M0)P(M1)P(M3)P(Mge 1)$$

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I have questions about **mans pecs on full display** and **guy** in this context? closed

The term "guy" refers to the consumer, the average person watching the show. The phrase "pecs" refers to pectoral muscles, which lie under the chest. So a simplification might be "pectorals" or merely "chest," though this latter phrase loses some of the meaning. "On full display" might be paraphrased as "clearly visible" or "there for the whole world to see."

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What pair of shorts match this outfit?

Well I would go with the color black since thats what the hat is rimmed with and you don't want to much teal, as for the fabric I would go with the same fabric the clothes your looking at are made from, the style you could go from cargo to classic khaki type of a short I guess

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How to make this look cool?

I love Cobra Starship, and Gabe is hoot :)

anyway, wear the hoodie however you want it, no one will judge you by the colour of your shirt, especially if they already know you as a straight person.

but i would say to keep it completely unzipped.

because from my exprience, only girls zip it up halfway x)

good luckkk

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What is acceptable outerwear for a date?

A jacket, cable-knit looks good, in a netural color (browns, grays, dark blues, dark greens, ect.) And like a vest, not the dorky kind. Something that has the faux-fur lining the hood looks really good. Also you can wear Uggs, with jeans with the holes.

Heres a link of what i mean:

http://www.polyvore.com/cgi/set?id1400071

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Politics: Are you shocked Liberals love Obama policies after 90% of them are Bush?

Why do put the 2012-GOP-Election., Romney/his Political- Advidors, GOP-Super-PACS and Tea-Party Math, online? Arent you guys embarrassed enougy? ( I left the Mothers out. Why you guys don't include them in anything of importance, Do you guys Respect or like Females?, ask some Mothers how they feel when you GOP guys dog them in public.) justasking pot-p-s y-p-s?

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Can anyone check if this is correct?

I think the answer is $86400$: Arrange the women: $6!$ ways. There are now $5$ possible spots for men: W-W-W-W-W-W (we must pick four of the five spots between two women to place the men). There are $5$ ways to choose $4$ of these $5$ spots. There are then $4!$ ways to arrange the men.Total: $6!cdot 5cdot 4!86400$.This agrees with mvw's answer, but arrived at differently

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What would you label me (long)?

i think we could be greater united as people, by using fact we're not defining somebody via one single function. to illustrate, by using fact somebody is gay, we in many cases anticipate they comprehend approximately stuff to do with their sexual orientation, yet would possibly not, quite in the event that they these days got here out

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why can't i get a guy?

None of those things will keep you from getting a boyfriend except not talking. And even then, when you meet the right guy you'll talk up a storm. Don't worry about it. All of your "stuff" is probably keeping you from hooking up with the wrong guy. The right guy will like everything about you

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Combinations Math - Choosing from juries

There are $binom607$ ways to choose $7$ people from $60$.Choosing $4$ men from a room say room A, is $binom84$ and $3$ from other three rooms, each gives $binom73 $ways to choose. This is $3* binom73$ (added for each room)Now, since we have $4$ rooms for men, so by symmetry, the total favourable cases are :$$4* (binom84 * ( 3 * binom73 ) ) $$Therefore, the probability is$$

frac29400386206920approx 7.612*10^-5$$

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Gender roles for a jungle treehouse culture

It is certainly possible man physical advantage or woman doesn't make that much of difference when it come to hunt since must hunters are ambush hunters who will not actually be fighting with there prey.The odds of a culture like this forming increase if there is a low population of men and constant chance of attacks from hostile tribes

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How many distinct football teams of 11 players can be formed with 33 men?

Number of ways of choosing $r$ people from a set of $n$ people is given by $$dbinomnr$$ In your case, you want to choose $11$ men from a set of $33$ men. Hence, the number of ways is $$dbinom3311 dfrac33 times 32 times 31 times 30 times 29 times 28 times 27 times 26 times 25 times 24 times 2311 times 10 times 9 times 8 times 7 times 6 times 5 times 4 times 3 times 2 times 1 193536720$$

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help me name my characters please?

Allen Seaver

Allen Naughton

Allen Reinhart

Name for your girl: Amethyst Parker - Cole She could be Ame (Amy) for short if you want a more common first name.

(Amethyst is a purple gem. The hyphenated last name because of her parents. Her mother's surname is "Parker," her father's is "Cole").

Good luck.

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Are the Nazgl Blind?

Kind of, they see the world differently, from another realm of sorts, they can sense the world around them but they don't see it the same way. The can also sense the world through their mounts, which is why they always use some kind of mount. As for the ring, it's a bridge between realms it shows up in both.

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Where to find wilderness in Europe?

Northern Sweden, yes. But also northern Norway (Svalbard!). Greenland (if that counts as Europe).

There are some old forests that may be of interest as well. Brading on Isle of Wight. Rautas in Kiruna, Sweden. Tyresta National Park quite close to Stockholm, Sweden is quite accessible. Biaowiea Forest in Poland... Also in Latvia you can find untouched areas.

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A verb for a 'swarm' of men? closed

You could also use the word; horde.A horde is a disparaging word for a large group of people, as in hordes of fans descended on the stage. Instances of hoard being used instead of horde are not uncommon: around a quarter of citations for hoard in the Oxford English Corpus are for the incorrect use.Oxford Dictionary of English

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All men today are safek zav?

Tzitz Eliezer X:1 and Minchat Yitzchak V:1 both quote the opinion of Chazon Nachum Kelim 1:6 that nowadays one needs to treat himself as a zav, and use this as part of their arguments to prohibit ascending har habayit.Those poskim who permit ascending har habayit (without requiring shiv'ah nekiyyim and tevilah bemayim chayyim) presumably are not concerned for this opinion

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is your school dress code strict?

no, not anymore. now we don't have a dress code

but last year this was the dress code:

1) straps have to be three fingers wide

2) shorts have to be as long as the the finger tips end when arms are extended

3) when you extend arms all the way up your shirt can't show any skin and can't ride up

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why did this random guy do this to me?

you should of put a pic up of what you were wearing that day..cause when you see that pic i immediately think he was totally right no wonder.

cause i can't imagine what you would look like with what you say you were wearing that day maybe you should put pic up of you in that outfit instead.

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Why doesn't Agent J remember his father?

According to Agent J Wikipedia articleJames was left with no clear understanding of why his father wasn't around when he grew up, with nothing but his father's pocket watch to remember him by.nothing but his father's pocket watch...So he got no photo to rely on, just the pocket watch. He just don't remember how his father was looking.

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Comparing two groups with unequal sizes?

Assuming that your response variable fulfills the assumptions made for a t-test (normality of sample mean etc.) and your only concern is that your two groups are different in size and/or variance, then you can use Welch's t-test, which takes care of exactly those concerns while addressing the same issue, namely whether the means are statistically different or not

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In how many ways can you form a committee of three from a set of $10$ men and $8$ women, such that there is at least one woman in the committee?

Suppose $w_1$ was the first woman chosen among possible $8$, then say $m_1,w_3$ were chosen. So your committee is $w_1,m_1,w_3$.In your way of counting: what if $w_3$ is chosen as the first woman, followed by $m_1, w_1$? Then too the committee is same as before ($w_3,m_1,w_1$) but you are counting this as a different committee

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Do we need a men tag?

The most probable on-topic questions would likely be about men's grooming products, men's clothing, or male health (as the question referred to is) ... or maybe, just maybe, about men's behaviour/psychology/ethics (slippery ... slope ... into ... a ... pro... or ... anti ...social ... justice ... site ... bias ...) ....For the three (or four) categories, firmly establishing a canonical tag now might be a good idea.

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Finding perfect matchings with as few database queries as possible

Here is how to solve this in time $O(n^2)$, where $n$ is the number of women (or men). For each man and each woman, ask the database how many matches does the set consisting only of the two of them contain.Presumably you can solve this much faster than $O(n^2)$, but this gives you something to start with.

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Find the probability that the 8th woman to appear is in 17th position.

HINT: Choose $1$ woman from $15$ and put her to $17^th$ position. Then from the rest of $14$, choose $7$ of them; and from $10$ men choose $9$ of them and permute them in the positions $1-16$. Then, permute the rest of people in the positions $18-25$. EDIT: Just to verify my answer with the other two answers, the answer is

$$fracdbinom151dbinom147dbinom10916!8!25! approx 0.028$$

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Simple elementary school ratio question closed

I'm not sure exactly what you want. We know that there are $5k$ men and $3k$ women, for some value of $k$. We also know that there are half as many children as adults, so there are $4k$ children. Therefore, the desired ratio is as you say.

I don't know that this is any more "algebraic" than what you did

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Why are military men often chauvinistic, womanizing, homophobic jerks?

for most men they are in the military for the male dominant adrenaline rush / duty to their country as a "man" / military is power so power is what i need to portray state of mind. so it's their way of getting that off as being that image. it's not the right way to do it but it's what satisfies them.

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Suppose that each of $n$ men at a party throws his hat into the center of the room

By the Inclusion Exclusion principle, we have $$P(cup A_i)sum P(A_i)-sum P(A_icap A_j)ldots(-1)^n1sum P(cap A_i),$$where $A_i$ is the event that the $i^th$ person picks his own hat.A hint: $$P(A_1cap A_2capldotscap A_k)frac(n-k)!n!$$